A man can row a boat in still water at a speed of 5 m/s. He covers a stretch of 200 m in a river downstream during high and low tides in 10 s and 25 s respectively. What is the ratio of the speed (in m/s) of the water flowing in the river during high and low tides?

Let's assume the speed of the water flowing in the river during high and low tides are 'a' and 'b' respectively.

A man can row a boat in still water at a speed of 5 m/s. He covers a stretch of 200 m in a river downstream during high and low tides in 10 s and 25 s respectively.

$$\frac{200}{5+a}\ =\ 10$$

20 = 5+a

a = 20-5

a = 15

$$\frac{200}{5+b}\ =\ 25$$

$$\frac{8}{5+b}\ =\ 1$$

8 = 5+b

b = 8-5

b = 3

The ratio of the speed of the water flowing in the river during high and low tides ==> a : b

15 : 3

5 : 1