Question 64

Two chords AB and CD of a circle when produced, meet at a point P outside the circle. If AB = 6 cm, PB = 5 cm, PD = 4 cm, then CD is equalto:

Solution

Two chords AB and CD of a circle when produced, meet at a point P outside the circle then

$$PA\times\ PB=PC\times\ PD$$

PA=11, PC=(x+4)

$$11\times\ 5=\left(x+4\right)\times\ 4$$

$$55=4x+16$$

$$4x=39$$

$$x=9.75$$

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