The total number of female students specialising in B and C is what per cent of the total number of students specialising in C and D (correct to one decimal place)?

Total Students specializing in B = $$\frac{97.2}{360}\times\ 2400\ =\ 648$$ and female students = $$\frac{14}{27}\times\ 648=336$$.
Total Students specializing in C = $$\frac{54}{360}\times\ 2400\ =\ 360$$ and female students = $$\frac{8}{15}\times\ 360\ =\ 192$$.
Total female students = 336 + 192 = 528.

Total Students specializing in D = $$\frac{72}{360}\times\ 2400\ =\ 480$$. 
Total students specializing in C and D = 480 + 360 = 840.
Required percentage = $$\frac{528}{840}\times\ 100\ =\ 62.85\approx\ 62.9\%$$.