If an 8-digit number 30x558y2 is divisible by 88, then the value of (6x +6y) is:

Given, 8-digit number 30x558y2 is divisible by 88 then the number must be divisible by 11

If it is divisible by 11 then,

Sum of digits at even place - Sum of digits at odd place = 0 or multiple of 11

$$=$$> (0+5+8+2)-(3+x+5+y) = 0 or multiple of 11

$$=$$> 15-8-(x+y) = 0 or multiple of 11

$$=$$> 7-(x+y) = 0 or multiple of 11

If 7-(x+y) = multiple of 11 then x+y is negative which is not a possible case

$$=$$> 7-(x+y) = 0

$$=$$> x+y = 7

$$\therefore\ $$6x+6y = 6(x+y) = 6(7) = 42

Hence, the correct answer is Option C