A can complete a task in 8 days and B in 16 days respectively. If they work together for 3 days, then the remaining part of the work left is:
Let the total work be 16 units (LCM of 8 and 16)
Efficiency of A = 16/8 = 2 units/day
Efficiency of B = 16/16 = 1 unit/day
Total work done in 1 day = 3 units
Then, In 3 days, 9 units of work will be completed.
Remaining part of work = $$ \dfrac{16-9}{16} = \dfrac{7}{16}$$
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