The total surface area of a closed hemisphere is 16632 $$cm^{2}$$. What is the sum of the radius and the diameter of this hemisphere? [Use $$\pi = \frac{22}{7}$$]

The total surface area of a closed hemisphere is 16632 $$cm^{2}$$.

total surface area of a closed hemisphere = $$3\times\ \pi\ \times\left(radius\right)^2$$

$$16632=3\times\frac{22}{7}\ \times\left(radius\right)^2$$

$$16632=\frac{66}{7}\ \times\left(radius\right)^2$$

$$252=\frac{1}{7}\ \times\left(radius\right)^2$$
$$1764=radius^2$$
$$42^2=radius^2$$
radius = 42 cm

Sum of the radius and the diameter of this hemisphere = $$radius+2\times radius$$

= $$3\times radius$$

= $$3\times42$$

= 126 cm