Question 63

Abhi sold two articles for ₹5,220 each. On one, he gained 16% and on the other, he lost 10%. His profit or loss on the whole was:

Solution

It is given that the price of the each two article$$=5220$$
Let the cost price of the first article $$=xR$$

On the first article, he gained profit $$16\%$$

So, $$Profit=\dfrac{(Selling price-Cost price)\times 100}{cost price}$$

$$16=\dfrac{(5220-x)\times 100}{x}$$
$$16x=5220\times 100-100x$$
$$116x=5220\times 100$$
$$x=\dfrac{5220\times 100}{116}=4500$$

So, profit amount $$=5220-4500=720Rs$$
Let cost price of the second article =Y
On the second article he lost 10%
So, $$loss=\dfrac{(Cost price-Selling price)\times 100}{cost price}$$

$$10=\dfrac{(Y-5220)\times 100}{Y}$$
$$10Y=100Y-5220\times 100$$
$$90Y=5220\times 100$$
$$Y=\dfrac{5220\times 100}{90}=5800Rs.$$

Hence, loss amount on the second article$$ =5800-5220 = 580Rs.$$

Hence, net gain$$=720-580=140Rs.$$


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