The ratio of total number of male students specialising in B and C to the total number of female students specialising in A, D and E is:

Number of Male students specializing in B = $$\frac{13}{27}\times\ \frac{97.2}{360}\times\ 2400\ =\ 312$$,
Number of Male students specializing in C = $$\frac{7}{15}\times\ \frac{54}{360}\times\ 2400\ =\ 168$$.

Number of female students specializing in A = $$\frac{8}{17}\times\ \frac{61.2}{360}\times\ 2400\ =\ 192$$,
Number of female students specializing in D = $$\frac{3}{10}\times\ \frac{72}{360}\times\ 2400\ =\ 144$$ and,
Number of female students specializing in E = $$\frac{11}{21}\times\ \frac{75.6}{360}\times\ 2400\ =\ 264$$.

The ratio of total number of male students specialising in B and C to the total number of female students specialising in A, D and E is 480 : 600 = 4:5.