Question 62

If the length of a rectangle is decreased by 11% and the breadth is increased by 11%, its area will undergo:

Solution

Let the Length and Breadth are $$x,y$$ respectively.

$$\therefore$$ Initial Area = $$xy$$

As Given, Length is decreased by 11% and breadth is increased by 11% So,

New Length = $$x \times \frac{89}{100} = \frac{89x}{100}$$

New Breadth = $$y \times \frac{111}{100} = \frac{111y}{100}$$

New Area = $$\frac{89x}{100}\times \frac{111y}{100}= \frac{9879xy}{10000} = 0.9879xy$$

Change in Area = $$ 0.9879xy - xy = - 0.0121xy$$

% Change = $$\frac{-0.0121xy}{xy} \times 100 = -1.21$$

           


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