A train passes a platform in 42 seconds and a man standing on the platform in 25 seconds. If the speed of the train is 72 km/hr, what is the length of the platform?
Given, Speed of the train = 72 km/hr = $$72\times\dfrac{5}{18} = 20 m/sec$$
Time taken to cross a man on the platform = 25 seconds
Let the length of the train be T m and length of the platform be P m.
Given, $$\dfrac{T}{25} = 20 => T = 500$$
Hence, The length of the train = 500 m
Given, $$\dfrac{500+P}{42} = 20 => 500+P = 840 => P = 340$$
Therefore, The length of the platform = 340 m
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