The least integral value $$\alpha$$ of $$x$$ such that $$\frac{x-5}{x^2+5x-14} > 0$$, satisfies :

A

$$\alpha^2 + 3\alpha - 4 = 0$$

B

$$\alpha^2 - 5\alpha + 4 = 0$$

C

$$\alpha^2 - 7\alpha + 6 = 0$$

D

$$\alpha^2 + 5\alpha - 6 = 0$$