Question 61

If the 8-digit number 2074x4y2 is divisible by 88, then the value of (4x + 3y) is:

Solution

Given that 2074x4y2 is divisible by 88,

This will be divisible by 88 if, it is individually divisible by 11 and 8.

Divisibility by - Any number is divisible by 8, if the last 3 digit of that number is divisible by 8.

4y2  it will be divisible by 8 if, y=3 or y=7

Divisibility by 11- Any number is divisible by 11 if the difference between the sum of odd place digit and sum of even place digit is divisible by 11.

$$2+4+4+0-x-y-7-2=1-x-y$$

Now y=3 then x=9

if y=7 then x=5

Now, substituting the values in the equation,

if x=9 and y=3 then $$ (4x + 3y)=4\times 9+3\times 3=36+9=45 $$

if x=5 and y=7 then$$ (4x + 3y)=4\times 5+3\times 7=20+21=41$$


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