Question 60

Ina circle with centre O, an are ABC subtends an angle of $$110^\circ$$ at the centre of the circle. The chord AB is produced to a point P. Then $$\angle$$CBP is equal to:

Solution

Take any point D on the circumference and join AD and DC .

∴ $$\angle$$AOC = 2 × $$\angle$$ADC

⇒ $$\angle$$ADC = 1/2 × $$\angle$$AOC = 1/2 × 110 = 55$$^\circ$$

Now, $$\angle$$PBC = ∠ADC [exterior angle of cyclic quadrilateral]

⇒ $$\angle$$PBC = 55$$^\circ$$

SO , the answer would be option b)55$$^\circ$$.


Create a FREE account and get:

  • Free SSC Study Material - 18000 Questions
  • 230+ SSC previous papers with solutions PDF
  • 100+ SSC Online Tests for Free

cracku

Boost your Prep!

Download App