In what ratio is the segment joining (-1,-12) and (3,4) divided by the x-axis?

Using section formula, the coordinates of point that divides line joining A = $$(x_1 , y_1)$$ and B = $$(x_2 , y_2)$$ in the ratio a : b

= $$(\frac{a x_2 + b x_1}{a + b} , \frac{a y_2 + b y_1}{a + b})$$

Let the ratio in which the segment joining (-1,-12) and (3,4) divided by the x-axis = $$k$$ : $$1$$

Since, the line segment is divided by x-axis, thus y coordinate of the point will be zero, let the point of intersection = $$(x,0)$$

Now, point P (x,0) divides (-1,-12) and (3,4) in ratio = k : 1

=> $$0 = \frac{(4 \times k) + (-12 \times 1)}{k + 1}$$

=> $$4k - 12 = 0$$

=> $$k = \frac{12}{4} = 3$$

$$\therefore$$ Required ratio = 3 : 1

=> Ans - (C)