The pressure acting on a submarine is $$3 \times 10^5$$ Pa at a certain depth. If the depth is doubled, the percentage increase in the pressure acting on the submarine would be: (Assume that atmospheric pressure is $$1 \times 10^5$$ Pa, density of water is $$10^3$$ kg m$$^{-3}$$, g = 10 ms$$^{-2}$$)

A

$$\frac{200}{3}$$%

B

$$\frac{200}{5}$$%

C

$$\frac{5}{200}$$%

D

$$\frac{3}{200}$$%