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Consider the two similar triangles ABC and DEF. Which of the following is correct about the ratio of the area of the triangle ABC and DEF?
It is given that $$\triangle$$ ABC $$\sim\triangle$$ DEF
=> $$\frac{AB}{DE}=$$ $$\frac{BC}{EF}=$$ $$\frac{AC}{DF}$$
Also, ratio of areas of two similar triangles is equal to the ratio of the square of the corresponding sides.
=> $$\frac{ar(\triangle ABC)}{ar(\triangle DEF)}=$$ $$(\frac{AB}{DE})^2=(\frac{BC}{EF})^2=(\frac{AC}{DF})^2$$
=> Ans - (B)
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