Question 58

If a+b=2c, then the value of $$\frac{a}{a-c}+\frac{c}{b-c}$$ is equal to where $$a\neq b \neq c$$

Solution

Given : $$a+b=2c$$

=> $$a+b=c+c$$

=> $$a-c=c-b$$ ----------(i)

To find : $$\frac{a}{a-c}+\frac{c}{b-c}$$

= $$\frac{a}{c-b}-\frac{c}{c-b}$$ [Using equation (i)]

= $$\frac{a-c}{c-b}$$

= $$\frac{c-b}{c-b}=1$$

=> Ans - (B)

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