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Question 57
What should come in place of the question mark (?) in the following equation?
$$(?)^{2} +? + 12^{3} = 13^{2} + 22^{2} + 2715$$
Solution
Let's assume 'y' in place of the question mark.
$$(y)^{2} + y + 12^{3} = 13^{2} + 22^{2} + 2715$$
$$y^2+y+1728=169+484+2715$$
$$y^2+y+1728=3368$$
$$y^2+y+1728-3368=0$$
$$y^2+y-1640=0$$
$$y^2+(41-40)y-1640=0$$
$$y^2+41y-40y-1640=0$$
$$y(y+41)-40(y+41)=0$$
(y+41)Â (y-40) = 0
y = -41, 40
As per the given options, '40' will come in place of the question mark.
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