Question 57
The average of nine numbers is 20. If two of these numbers are removed, then the average becomes 18. What is the sum of the two numbers that are removed?
Solution
The average of nine numbers is 20.
Sum of nine numbers = $$20\times9$$ = 180 Eq.(i)
If two of these numbers are removed, then the average becomes 18.
Sum of remaining seven numbers = $$18\times7$$ = 126 Eq.(ii)
Sum of the two numbers that are removed = Eq.(i)-Eq.(ii)
= 180-126
= 54
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