If $$( x - 5)^{2}$$ + $$(y - 2)^{2}$$ + $$(z - 9)^{2}$$ = 0 , then value of (x + y - z) is
Expression : $$( x - 5)^{2}$$ + $$(y - 2)^{2}$$ + $$(z - 9)^{2}$$ = 0
$$\because$$ If sum of three positive numbers is zero, then the numbers are equal to zero
=> $$(x-5)^2=0$$
=> $$(x-5)=0$$
=> $$x=5$$
Similarly, $$y=2$$ and $$z=9$$
To find : $$(x+y-z)$$
= $$5+2-9=-2$$
=> Ans - (C)
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