Solution
Given, $$a^3-b^3=899$$ and $$a-b=31$$
$$=$$> $$\left(a-b\right)\left(a^2+ab+b^2\right)=899$$
$$=$$> $$31\left(a^2+ab+b^2-2ab+2ab\right)=899$$
$$=$$> $$\left(a-b\right)^2+3ab=\frac{899}{31}$$
$$=$$> $$\left(a-b\right)^2+3ab=29$$
Hence, the correct answer is Option D
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