In a circle, two equal and parallel chords are 6 cm apart and they lie on the opposite sides of the centre of the circle, whose radius is 5 cm. The length of each chord (in cm), is:

Given,

radius of the circle = 5 cm

The length of two chords are equal, then the perpendicular distance of the chords from the centre are equal

$$=$$>  OA = OB

Distance between parallel chords = 6 cm

$$=$$>  AB = 6

$$=$$>  OA + OB = 6

$$=$$>  OA + OA = 6

$$=$$>  2OA = 6

$$=$$>  OA = 3cm

$$=$$>  OA = OB = 3cm

From the figure,

In $$\triangle\ $$OBC

$$OB^2+BC^2=OC^2$$

$$=$$>  $$3^2+BC^2=5^2$$

$$=$$>  $$9+BC^2=25$$

$$=$$>  $$BC^2=16$$

$$=$$>  $$BC=4$$ cm

$$\therefore\ $$Length of each chord = 2BC = 2(4) = 8 cm

Hence, the correct answer is Option A