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$$2.7$$ kg of each of water and acetic acid are mixed. The freezing point of the solution will be $$-x°C$$. Consider the acetic acid does not dimerise in water, nor dissociates in water. $$x =$$ ______ (nearest integer) [Given: Molar mass of water $$= 18$$ g mol$$^{-1}$$, acetic acid $$= 60$$ g mol$$^{-1}$$, $$K_f$$ H$$_2$$O: $$1.86$$ K kg mol$$^{-1}$$, $$K_f$$ acetic acid: $$3.90$$ K kg mol$$^{-1}$$, freezing point: H$$_2$$O $$= 273$$ K, acetic acid $$= 290$$ K]
Correct Answer: 31
ΔTf=Kf×m. Solvent is water (2.7kg). Solute is acetic acid: 2700/60=45 mol. m=45/2.7=16.67.
ΔTf=1.86×16.67=31°C. Freezing point = 0-31=-31°C.
The answer is $$\boxed{31}$$.
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