12 persons can complete half of a work in 9 days. How many persons can complete the same work (whole) in 6 days?
We know that $$\dfrac{M_1 \times D_1}{W_1} = \dfrac{M_2 \times D_2}{W_2}$$ where M = No. of men, D = No. of days and W = Work
$$\dfrac{12 \times 9}{\dfrac{1}{2}} = \dfrac{M_2 \times 6}{1}$$
=> $$M_2 = \dfrac{12\times 9\times 2}{6} = 36$$
Therefore, 36 men are required to complete whole work in 6 days.
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