Question 52

The Table shows the number of candidates appearing for an interview for a post in six Banks (H, I, J, K, L, M) and percentage of qualifying candidates.

The number of candidates who did not qualify in bank K was approximately what percent(correct to nearest integer) of the candidates who did not qualify in bank I?

Solution

The number of candidates who did not qualify in bank K = 980 of (100-20)%

= 980 of 80%

= 784

The number of candidates who did not qualify in bank I = 2200 of (100-26)%

= 2200 of 74%

= 1628

Percentage = $$\frac{784}{1628}\times\ 100$$

= 48.157%

= 48% (approx.)

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