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The Table shows the number of candidates appearing for an interview for a post in six Banks (H, I, J, K, L, M) and percentage of qualifying candidates.
The number of candidates who did not qualify in bank K was approximately what percent(correct to nearest integer) of the candidates who did not qualify in bank I?
The number of candidates who did not qualify in bank K = 980 of (100-20)%
= 980 of 80%
= 784
The number of candidates who did not qualify in bank I = 2200 of (100-26)%
= 2200 of 74%
= 1628
Percentage = $$\frac{784}{1628}\times\ 100$$
= 48.157%
= 48% (approx.)
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