Question 52
The Table shows the number of candidates appearing for an interview for a post in six Banks (H, I, J, K, L, M) and percentage of qualifying candidates.
The number of candidates who did not qualify in bank K was approximately what percent(correct to nearest integer) of the candidates who did not qualify in bank I?
Solution
The number of candidates who did not qualify in bank K = 980 of (100-20)%
= 980 of 80%
= 784
The number of candidates who did not qualify in bank I = 2200 of (100-26)%
= 2200 of 74%
= 1628
Percentage = $$\frac{784}{1628}\times\ 100$$
= 48.157%
= 48% (approx.)
Create a FREE account and get:
- Free SSC Study Material - 18000 Questions
- 230+ SSC previous papers with solutions PDF
- 100+ SSC Online Tests for Free
