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Explanation
The starting compound is salicylic acid, which contains a phenolic $$-OH$$ group and a carboxylic acid $$-COOH$$ group.
In reaction X, salicylic acid is converted into acetylsalicylic acid (aspirin). During this transformation, the phenolic $$-OH$$ group is converted into an acetate ester $$(-OCOCH_3)$$, while the carboxylic acid group remains unchanged.
This transformation requires acetylation of the phenolic hydroxyl group. Acetic anhydride in the presence of an acid catalyst is commonly used for this purpose.
Therefore,
$$X=(CH_3CO)_2O/H^+$$
In reaction Y, salicylic acid is converted into methyl salicylate. In this transformation, the carboxylic acid group is converted into a methyl ester $$(-COOCH_3)$$, while the phenolic $$-OH$$ group remains unchanged.
This conversion is achieved by Fischer esterification using methanol in the presence of an acid catalyst and heat.
Therefore, $$Y=CH_3OH/H^+,\Delta$$
Hence, $$X=(CH_3CO)_2O/H^+$$ and $$Y=CH_3OH/H^+,\Delta$$
Therefore, the correct answer is $$\text{Option A}$$
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