A block of mass 1 kg is pushed up a surface inclined to horizontal at an angle of $$60°$$ by a force of 10 N parallel to the inclined surface as shown in figure. When the block is pushed up by 10 m along inclined surface, the work done against frictional force is : $$g = 10$$ m s$$^{-2}$$

A

$$5\sqrt{3}$$ J

B

5 J

C

$$5 \times 10^3$$ J

D

10 J