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In the isolation of metals, calcination is a process where the ore is heated strongly in the absence of air or in a limited supply of air. This step is crucial for removing volatile impurities and converting the ore into a more suitable form for reduction.
Let us consider common types of ores and what happens during calcination:
For carbonate ores, such as zinc carbonate (ZnCO₃) or limestone (CaCO₃), calcination causes decomposition. The reaction for zinc carbonate is:
$$ \text{ZnCO}_3 \rightarrow \text{ZnO} + \text{CO}_2 $$Here, zinc carbonate decomposes to zinc oxide (a metal oxide) and carbon dioxide gas.
For hydrated ores, like bauxite (Al₂O₃·2H₂O), calcination removes water of hydration:
$$ \text{Al}_2\text{O}_3 \cdot 2\text{H}_2\text{O} \rightarrow \text{Al}_2\text{O}_3 + 2\text{H}_2\text{O} $$This yields aluminium oxide (a metal oxide).
For hydroxide ores, such as iron(III) hydroxide, calcination leads to decomposition:
$$ 2\text{Fe(OH)}_3 \rightarrow \text{Fe}_2\text{O}_3 + 3\text{H}_2\text{O} $$This produces iron(III) oxide (a metal oxide).
Now, examining the options:
Option B: Metal carbonate - Calcination decomposes carbonates, so it does not result in a carbonate.
Option C: Metal sulphide - Sulphide ores are typically roasted (heated in excess air) to form oxides, not calcined to sulphides.
Option D: Metal hydroxide - Hydroxides decompose to oxides upon heating, so calcination does not yield hydroxides.
In all cases, calcination produces metal oxides. Hence, the correct answer is Option A.
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