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A tree bends due to heavy storm and now its peak touches the ground making an angle of $$30^{\circ}$$ with it. If the bent part is 20 metre long, find the original height of the tree in metres.

BC is ground and it is given that $$\angle\ ACB\ =30^{\circ\ }$$
Actual length of the tree = AB + AC
$$\sin30^{\circ\ }=\frac{AB}{AC}$$
AB = 20/2 = 10 cm
Length of the tree = AB + AC = 10 + 20 = 30 cm
Answer is option D.
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