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Aniline does not undergo Friedel-Crafts alkylation or Friedel-Crafts acylation.
This is because aniline reacts with the Lewis acid catalyst:
$$\mathrm{AlCl_3}$$
to form a salt.
$$\mathrm{C_6H_5NH_2 + AlCl_3 \longrightarrow C_6H_5NH_2^+AlCl_4^-}$$
Due to salt formation, the nitrogen atom acquires a positive charge.
$$\mathrm{-NH_2 \longrightarrow -NH_2^+}$$
The positively charged amino group becomes strongly electron-withdrawing and acts as a strong deactivating group.
Hence, the benzene ring becomes less reactive towards electrophilic substitution.
Therefore:
$$\mathrm{Friedel\text{-}Crafts\ Alkylation\ and\ Acylation\ do\ not\ occur}$$
However, other electrophilic substitution reactions such as:
$$\mathrm{Nitration,\ Halogenation,\ and\ Sulphonation}$$
can still take place under suitable conditions.
Thus, the right option is C.
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