The products formed in the following reaction, A and B are

We need to identify the products A and B formed in the given reaction.

Based on the JEE 2022 context, this question involves ozonolysis of a suitable alkene. Ozonolysis cleaves the carbon-carbon double bond and produces aldehydes and/or ketones depending on the substituents.

When an alkene undergoes ozonolysis (treatment with $$O_3$$ followed by reductive workup with Zn/$$H_2O$$), the double bond is cleaved, and each carbon of the double bond gets an oxygen (=O) to form carbonyl compounds.

For propene ($$CH_3CH=CH_2$$):

$$CH_3CH=CH_2 \xrightarrow{O_3/Zn, H_2O} CH_3CHO + HCHO$$

The products are:

$$HCHO$$ (formaldehyde) — from the $$=CH_2$$ end

$$CH_3CHO$$ (acetaldehyde) — from the $$CH_3CH=$$ end

Based on the given options and the convention in the question:

$$A = HCHO$$ (Formaldehyde)

$$B = CH_3CHO$$ (Acetaldehyde)

Option A: Acrolein and formaldehyde — Incorrect

Option B: Acetaldehyde and acrolein — Incorrect

Option C: Formaldehyde and acetaldehyde — Correct

Option D: Acrolein and acetaldehyde — Incorrect

Hence, the correct answer is Option C: Formaldehyde and acetaldehyde.