Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Explanation: Benzene first undergoes Friedel-Crafts alkylation with isopropyl chloride in the presence of $$AlCl_3$$ to form cumene.
Cumene is oxidized by air to form cumene hydroperoxide, which on acidic hydrolysis gives phenol.
Therefore, intermediate $$P$$ is phenol.
Phenol reacts with:
$$Na_2Cr_2O_7/H_2SO_4$$
to undergo oxidation and form $$p$$-benzoquinone.
Phenol also reacts with bromine in non-polar solvent $$CS_2$$ to undergo monobromination.
Since the $$-OH$$ group is ortho/para-directing and steric hindrance favors substitution at the para position, the major product formed is $$p$$-bromophenol.
Thus, $$A = p\text{-benzoquinone}$$, $$B = p\text{-bromophenol}$$. The right option is B.
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation