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The reaction occurs in presence of $$\mathrm{NaOH/EtOH}$$, which favours:
$$\mathrm{E2\ Elimination}$$
The base abstracts a $$\mathrm{\beta}$$-hydrogen adjacent to the carbon bearing chlorine.
Removal of the vinylic hydrogen is unfavourable, so the proton is removed from the neighbouring $$\mathrm{sp^3}$$ hybridised carbon containing the methyl group.
Simultaneously, the chloride ion leaves and a new $$\mathrm{\pi}$$ bond is formed.
This elimination produces a:
$$\mathrm{Conjugated\ Diene}$$
Conjugated dienes are highly stable due to delocalisation of $$\mathrm{\pi}$$ electrons.
Hence, the major product formed is the conjugated methylcyclopentadiene structure.
Correct Option: $$\mathrm{B}$$
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