Question 44

Alkaline oxidative fusion of $$MnO_2$$ gives "A" which on electrolytic oxidation in alkaline solution produces $$B$$. $$A$$ and $$B$$ respectively are:

Solution

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Alkaline oxidative fusion of MnO$$_2$$:

$$2MnO_2 + 4KOH + O_2 \rightarrow 2K_2MnO_4 + 2H_2O$$

A = MnO$$_4^{2-}$$ (manganate ion, green color).

Electrolytic oxidation in alkaline solution:

$$MnO_4^{2-} \rightarrow MnO_4^- + e^-$$

B = MnO$$_4^-$$ (permanganate ion, purple color).

The answer is Option (2): $$MnO_4^{2-}$$ and $$MnO_4^-$$.

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