The orange colour of $$K_2Cr_2O_7$$ and purple colour of $$KMnO_4$$ is due to

In $$K_2Cr_2O_7$$: Cr is in +6 oxidation state with electronic configuration $$d^0$$. Since there are no d-electrons, d-d transitions are impossible. The orange color arises from charge transfer transitions (ligand-to-metal charge transfer, LMCT), where electrons from oxygen ligands are transferred to empty d-orbitals of Cr$$^{6+}$$.

In $$KMnO_4$$: Mn is in +7 oxidation state with electronic configuration $$d^0$$. Again, no d-electrons means no d-d transitions. The intense purple color is due to charge transfer transitions (LMCT from oxygen to Mn$$^{7+}$$).

Both colors are due to charge transfer transitions, not d-d transitions.

The correct answer is Option 1: Charge transfer transition in both.