Match List-I with List-II

1. Electronic Distribution Breakdown

• A. Cr⁺² (Chromium ion): Neutral Chromium (Z = 24) has an exceptional configuration of [Ar] 3d⁵ 4s¹. Removing two electrons (one from 4s and one from 3d) yields [Ar] 3d⁴ (Matches with iii).
• B. Mn⁺ (Manganese ion): Neutral Manganese (Z = 25) has a configuration of [Ar] 3d⁵ 4s². Removing one electron from the 4s orbital yields [Ar] 3d⁵ 4s¹ (Matches with iv).
• C. Ni⁺² (Nickel ion): Neutral Nickel (Z = 28) has a configuration of [Ar] 3d⁸ 4s². Removing both 4s electrons leaves a configuration of [Ar] 3d⁸ (Matches with i).
• D. V⁺ (Vanadium ion): Neutral Vanadium (Z = 23) has a configuration of [Ar] 3d³ 4s². Removing one electron from the 4s orbital yields [Ar] 3d³ 4s¹ (Matches with ii).

2. Correct Matching Options

• Final Map: (A) → iii, (B) → iv, (C) → i, (D) → ii

3. Final Verification

• Correct Option: (A)-III, (B)-IV, (C)-I, (D)-II