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The quantity of silver deposited when one coulomb charge is passed through $$AgNO_3$$ solution :
We need to determine what quantity of silver is deposited when 1 coulomb of charge is passed through $$AgNO_3$$ solution. According to Faraday’s First Law of Electrolysis, the mass of a substance deposited at an electrode is directly proportional to the quantity of charge passed.
The mass deposited (m) is related to the charge (Q) by
$$ m = Z \times Q $$where $$Z$$ is the electrochemical equivalent and $$Q$$ is the charge in coulombs. The electrochemical equivalent $$Z$$ is defined as the mass of a substance deposited when 1 coulomb of charge is passed through the solution.
Substituting $$Q = 1$$ coulomb gives
$$ m = Z \times 1 = Z $$Therefore, the quantity of silver deposited is one electrochemical equivalent of silver.
The electrochemical equivalent of silver is
$$ Z = \frac{M}{nF} = \frac{108}{1 \times 96500} = 1.118 \times 10^{-3} $$ g,which shows that it is neither 1 g nor 0.1 g‐atom of silver. The chemical equivalent of silver would be deposited by one faraday (96500 C) of charge, not one coulomb.
Hence, the correct answer is Option (2): 1 electrochemical equivalent of silver.
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