A body of mass 10 kg is moving with an initial speed of 20 m s$$^{-1}$$. The body stops after 5 s due to friction between body and the floor. The value of the coefficient of friction is: (Take acceleration due to gravity $$g = 10$$ m s$$^{-2}$$)

Body of mass 10 kg, initial speed 20 m/s, stops in 5 s due to friction.

Find deceleration.

$$ a = \frac{v - u}{t} = \frac{0 - 20}{5} = -4 \text{ m/s}^2 $$

Find coefficient of friction.

The friction force causes deceleration: $$f = \mu mg = ma$$

$$ \mu = \frac{|a|}{g} = \frac{4}{10} = 0.4 $$

The answer is Option D: 0.4.

Predict your JEE Main percentile, rank & performance in seconds

Check Your Score Now

Ask our AI anything

AI can make mistakes. Please verify important information.

Download resources