Question 39

When the square of the difference of two natural numbers is subtracted from the square of the sum of the same two numbers and the result is divided by four, we get

Solution

Lets assume both the natural numbers as {a,b} , then manipulative calculation is :

$$\dfrac{(a+b)\ ^2-\left(a-b\right)^2\ }{4}\ =\ ab$$

The final obtained value is "ab" i.e product of both natural numbers .

We know that, always the property of HCF, LCM :

LCM{a,b} x HCF{a,b} = a x b = Product of the given two numbers.

Therefore 'ab' = product of LCM and HCF .

View More Questions From Temporary

Create a FREE account and get: