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Question 36
In ΔPQR, S and T are points on side PQ and PR respectively. ST is parallel to QR. If S divides PQ in the ratio 1:5 and length of QR is 15 cm, find ST?
Solution
ST is parallel to QR
Let PS = $$x$$ and SQ = $$5x$$
=> $$\frac{PS}{PQ} = \frac{ST}{QR}$$
=> $$\frac{x}{x + 5x} = \frac{ST}{15}$$
=> $$\frac{1}{6} = \frac{ST}{15}$$
=> $$ST = \frac{15}{6} = 2.5$$ cm
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