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We can draw the graph like this:
We have to basically find the area of ABCD
$$\triangle\ OAB$$ is a right angled triangle
Area of $$\triangle\ OAB=\dfrac{1}{2}\times\ OA\times\ OB=\dfrac{1}{2}\times\ 2\times\ 3=3$$ square units
Now we can see, ABCD is made by four such triangles $$\triangle\ OAB,\triangle\ OBC,\triangle\ OAD$$ and $$\triangle\ ODC$$
So, area of square ABCD = $$4\times\ 3$$ = $$12$$ square units.
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