Match List - I with List - II.

Choose the correct answer from the options given below

We need to match each compound with its molecular shape using VSEPR theory.

(A) BrF₅

Br has 7 valence electrons. With 5 F atoms bonded, there are 5 bond pairs and 1 lone pair.

Hybridization: $$sp^3d^2$$ (6 electron pairs)

Shape: Square pyramidal (II)

(B) [CrF₆]³⁻

Cr in [CrF₆]³⁻ has an oxidation state of +3. With 6 F atoms bonded, there are 6 bond pairs and 0 lone pairs.

Hybridization: $$sp^3d^2$$ or $$d^2sp^3$$

Shape: Octahedral (IV)

(C) O₃ (Ozone)

The central O atom has 2 bonding regions (one double bond and one coordinate bond to the terminal O atoms) and 1 lone pair.

Hybridization: $$sp^2$$

Shape: Bent (I)

(D) PCl₅

P has 5 valence electrons. With 5 Cl atoms bonded, there are 5 bond pairs and 0 lone pairs.

Hybridization: $$sp^3d$$

Shape: Trigonal bipyramidal (III)

Matching:

• A - II (Square pyramidal)
• B - IV (Octahedral)
• C - I (Bent)
• D - III (Trigonal bipyramidal)

Therefore, the correct answer is Option C.