For OF$$_2$$ molecule consider the following:
(A) Number of lone pairs on oxygen is 2.
(B) FOF angle is less than 104.5°.
(C) Oxidation state of O is -2.
(D) Molecule is bent 'V' shaped.
(E) Molecular geometry is linear.
Correct options are:

We need to identify the correct statements about OF$$_2$$.

(A) Number of lone pairs on oxygen is 2.

Oxygen has 6 valence electrons. In OF$$_2$$, it forms 2 bonds with F, leaving 2 lone pairs. CORRECT. ✓

(B) FOF angle is less than 104.5°.

OF$$_2$$ has 2 bond pairs and 2 lone pairs around O (similar to water). The lone pair-lone pair repulsion reduces the bond angle. The actual FOF angle is about 103°, which is less than 104.5°. CORRECT. ✓

(C) Oxidation state of O is -2.

In OF$$_2$$, fluorine is more electronegative than oxygen, so F has -1 oxidation state. Therefore, O has +2 oxidation state, not -2. INCORRECT.

(D) Molecule is bent V-shaped.

With 2 bond pairs and 2 lone pairs, the molecular geometry is bent (V-shaped). CORRECT. ✓

(E) Molecular geometry is linear.

The molecule is bent, not linear. INCORRECT.

Correct statements: A, B, D.

The correct answer is Option 4: A, B, D only.