Match List - I with List - II

LIST-I (Atomic number)	LIST-II (Block of periodic table)
(A) 37	I. p-block
(B) 78	II. d-block
(C) 52	III. f-block
(D) 65	IV. s-block

Choose the correct answer from the options given below:

We need to match atomic numbers with their blocks in the periodic table.

(A) Z = 37: This is Rubidium (Rb), which is in Group 1 → s-block (IV)

(B) Z = 78: This is Platinum (Pt), which is a transition metal → d-block (II)

(C) Z = 52: This is Tellurium (Te), which is in Group 16 → p-block (I)

(D) Z = 65: This is Terbium (Tb), which is a lanthanide → f-block (III)

The correct matching is: A-IV, B-II, C-I, D-III.

The correct answer is Option 4.