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A solution is prepared by adding 2 g of 'X' to 1 mole of water. Mass percent of 'X' in solution is
Mass of X = 2 g. Mass of water = 1 mole = 18 g.
Total mass of solution = 2 + 18 = 20 g.
Mass percent of X = $$\frac{2}{20} \times 100 = 10\%$$
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