Let $$A = \{(\alpha, \beta) \in \mathbf{R} \times \mathbf{R} : |\alpha - 1| \le 4 \text{ and } |\beta - 5| \le 6\}$$ and $$B = \{(\alpha, \beta) \in \mathbf{R} \times \mathbf{R} : 16(\alpha - 2)^2 + 9(\beta - 6)^2 \le 144\}$$. Then

A

$$B \subset A$$

B

$$A \cup B = \{(x,y) : -4 \le x \le 4, -1 \le y \le 11\}$$

C

neither $$A \subset B$$ nor $$B \subset A$$

D

$$A \subset B$$