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Question
3 identical containers are completely filled with water-milk mixtures in the ratio 2:3, 3:4 and 4:5 respectively. All these mixtures are poured into a bigger container. What fraction of mixture in the bigger container should be replaced by water so that the resulting mixture has equal quantities of water and milk?
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Answer
Let the container volume be 315 units.
So,
1st container : 126unit : 189unit
2nd container : 135unit : 180unit
3rd container : 140unit : 175unit
Quantity in bigger container : 401unit : 544unit
Let the amount taken out be 'x' units.
Then ,
401+x-(401/945)x = 544-(544/945)x
401+(544/945)x = 544-(544/945)x
1088x/945 = 143
x = 143*945/1088
x = 124.2
fraction required = 124.2/945 = 13/100 approx.
