Edit MetaData
3Â years, 2Â months ago
3 identical containers are completely filled with water-milk mixtures in the ratio 2:3, 3:4 and 4:5 respectively. All these mixtures are poured into a bigger container. What fraction of mixture in the bigger container should be replaced by water so that the resulting mixture has equal quantities of water and milk?
3Â years, 2Â months ago
Let the container volume be 315 units.
So,
1st container : 126unit : 189unit
2nd container : 135unit : 180unit
3rd container : 140unit : 175unit
Quantity in bigger container : 401unit : 544unit
Let the amount taken out be 'x' units.
Then ,
401+x-(401/945)x = 544-(544/945)x
401+(544/945)x = 544-(544/945)x
1088x/945 = 143
x = 143*945/1088
x = 124.2
fraction required = 124.2/945 = 13/100 approx.
Detailed syllabus & Topic-wise Weightage
By proceeding you agree to create your account
Free CAT Syllabus PDF will be sent to your email address soon !!!