Let $$\triangle ABC$$ be a triangle with $$Ab = AC$$ and $$D$$ be a point on $$BC$$ such that $$\angle BAD = 30^\circ$$. If E is a point on $$AC$$ such that $$AD = AE$$, then $$\angle CDE$$ equals

A

$$60^\circ$$

B

$$30^\circ$$

C

$$10^\circ$$

D

$$15^\circ$$