An electron beam is accelerated by a potential difference $$V$$ to hit a metallic target to produce X-rays. It produces continuous as well as characteristic X-rays. If $$\lambda_{min}$$ is the smallest possible wavelength of X-ray in the spectrum, the variation of $$\log\lambda_{min}$$ with $$\log V$$ is correctly represented in:

$$E = \frac{hc}{\lambda_{min}}$$

$$\frac{hc}{\lambda_{min}} = eV$$

$$\lambda_{min} = \frac{hc}{eV}$$

$$\log(\lambda_{min}) = \log\left(\frac{hc}{eV}\right)$$

$$\log(\lambda_{min}) = \log\left(\frac{hc}{e}\right) - \log(V)$$

The graph of $$\log \lambda_{min}$$ vs $$\log V$$ must be a straight line sloping downwards at an angle of $$135^\circ$$ with the positive $$\log V$$ axis (or $$45^\circ$$ with the negative axis). Option (B) correctly represents this.