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Question 22

In a coil of resistance 100 Ω, a current is induced by changing the magnetic flux through it as shown in the figure. The magnitude of change in flux through the coil is:

image

$$i = \frac{1}{R} \left| \frac{d\Phi}{dt} \right|$$

$$q = \int i \, dt = \frac{1}{R} \int d\Phi = \frac{\Delta \Phi}{R}$$

$$\Delta \Phi = q \times R$$

$$q = \text{Area of Triangle} = \frac{1}{2} \times \text{Base} \times \text{Height}$$

$$q = \frac{1}{2} \times 0.5 \times 10 = 2.5\ \text{C}$$

$$\Delta \Phi = 2.5\ \text{C} \times 100\ \Omega$$

$$\Delta \Phi = 250\ \text{Wb}$$

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